Logging 12*e3c: Is ln(e) Cancelled Out?

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When taking the logarithm of 12*e^(3c), it is important to apply the logarithmic property that states log(ab) = log(a) + log(b). This means you should calculate it as ln(12) + ln(e^(3c)). Since ln(e) equals 1, the expression simplifies to ln(12) + 3c. Therefore, the initial assumption that ln(e) cancels out is correct, but the full calculation requires considering ln(12) as well. Understanding these logarithmic properties is essential for accurate calculations.
Alexx1
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If you have to take the log of 12*e3c
Can I do it like this: 12*ln(e3c)?
So ln e fall away, so the result is: 12*3c = 36c
Or do I have to do it like this: ln(12*e3c?

I'm not sure of it.
 
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Use the rule that log(ab)=log(a)+log(b) and I'm sure things should fall into place :smile:
 


Mentallic said:
Use the rule that log(ab)=log(a)+log(b) and I'm sure things should fall into place :smile:

Thanks
 


No problem :smile:
 

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