- #1

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## Main Question or Discussion Point

For this function

[itex]y=\sqrt{2ln(x)+1}[/itex]

if I use the chain rule properly, should I be getting this answer?

[itex]\frac{dy}{dx}=\frac{2}{x} \times \frac{1}{2} \times \frac{1}{\sqrt{2ln(x)+1}}[/itex]

My aim of doing this is to verify that

[itex]\frac{dy}{dx}=\frac{1}{xy}[/itex]

[itex]y=\sqrt{2ln(x)+1}[/itex]

if I use the chain rule properly, should I be getting this answer?

[itex]\frac{dy}{dx}=\frac{2}{x} \times \frac{1}{2} \times \frac{1}{\sqrt{2ln(x)+1}}[/itex]

My aim of doing this is to verify that

[itex]\frac{dy}{dx}=\frac{1}{xy}[/itex]