- #1
JamesGoh
- 143
- 0
For this function
[itex]y=\sqrt{2ln(x)+1}[/itex]
if I use the chain rule properly, should I be getting this answer?
[itex]\frac{dy}{dx}=\frac{2}{x} \times \frac{1}{2} \times \frac{1}{\sqrt{2ln(x)+1}}[/itex]
My aim of doing this is to verify that
[itex]\frac{dy}{dx}=\frac{1}{xy}[/itex]
[itex]y=\sqrt{2ln(x)+1}[/itex]
if I use the chain rule properly, should I be getting this answer?
[itex]\frac{dy}{dx}=\frac{2}{x} \times \frac{1}{2} \times \frac{1}{\sqrt{2ln(x)+1}}[/itex]
My aim of doing this is to verify that
[itex]\frac{dy}{dx}=\frac{1}{xy}[/itex]