Logarithmic Differentiation with Respect to y

  • Thread starter Thread starter captainjack2000
  • Start date Start date
  • Tags Tags
    Differentiation
captainjack2000
Messages
96
Reaction score
0

Homework Statement


I am trying to differentiate log((x+(x^2+y^2)^0.5)/(-x+(x^2+y^2)^0.5)) with respect to y


Homework Equations



I know that d/dx of ln(x) = 1/x but i am getting really confused when it comes to differentiating wrt to y?

Can I have some help please!

The Attempt at a Solution

 
Physics news on Phys.org
Use the chain rule

\frac{d}{dy}= \frac{dx}{dy}*\frac{d}{dx}

So if you had to differentiate ln(x) w.r.t y

\frac{d}{dy}(lnx)= \frac{dx}{dy}*\frac{d}{dx}(lnx) = \frac{1}{x}*\frac{dx}{dy}
 
The argument is \frac{x+\sqrt{x^2+y^2}}{-x+\sqrt{x^2+y^2}}

So when differentiating with respect to y it looks like \frac{a+\sqrt{a+y^2}}{-a+\sqrt{a+y^2}}

where x is just treated as some constant a

So you just use the chain rule for that derivative

Does that look a little less confusing?
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top