Logarithmic function as an integral

Click For Summary
SUMMARY

The discussion focuses on proving the logarithmic function rules using the integral definition Log(x) = ∫[1,x] (1/t) dt. The user successfully demonstrates the product rule but encounters difficulties with the quotient rule, specifically Log(a/b) = Log(a) - Log(b). A suggested solution involves using substitution to show that Log(1/b) = -Log(b), allowing the user to combine this with the product rule for a complete proof.

PREREQUISITES
  • Understanding of integral calculus, specifically the properties of definite integrals.
  • Familiarity with logarithmic functions and their properties.
  • Knowledge of substitution techniques in integration.
  • Basic algebraic manipulation skills to handle logarithmic identities.
NEXT STEPS
  • Study the proof of the product rule for logarithmic functions using integrals.
  • Research substitution methods in integral calculus for deeper understanding.
  • Explore the relationship between logarithmic and exponential functions.
  • Practice problems involving the derivation of logarithmic identities from integral definitions.
USEFUL FOR

Students of calculus, mathematics educators, and anyone interested in the theoretical foundations of logarithmic functions and their properties.

JMR_2413
Messages
2
Reaction score
0

Homework Statement


I'm attempting to prove the rules for the logarithmic function using the Integral definition: Log(x)=[1,x]∫1/t dt. I think I am alright with the product rule but I'm struggling with the quotient rule: i.e. Log(a/b)=Log(a)-Log(b). I believe that I'm having trouble breaking up the Integral correctly. Any help would be appreciated!

Homework Equations





The Attempt at a Solution

 
Physics news on Phys.org
If you can show the product rule, then the quotient rule will follow the same logic, with an appropriate assumption about which of a or a/b is larger. Alternatively, use substitution to show that [itex]\log(1/b) = - \log b[/itex] so that you can combine this with the product rule.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
10
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
23
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 13 ·
Replies
13
Views
3K
Replies
4
Views
2K