LS Solution vs. Pre-Averaging: Which is More Effective for Noise Reduction?

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The discussion centers on comparing the effectiveness of Least Squares (LS) with the pseudo-inverse against a pre-averaging approach for noise reduction in a system of equations. The user seeks to solve for a small vector \mathbf{c} from a large, noisy vector \mathbf{y} and considers averaging consecutive elements in \mathbf{y} to reduce noise before applying LS. There is skepticism about whether pre-averaging improves results compared to directly using LS on the full noisy dataset. The conversation invites analytical proof regarding the properties of the pseudo-inverse to support or refute the effectiveness of the proposed averaging method. Overall, the focus is on determining the most efficient strategy for noise reduction in this context.
divB
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Hi,

I have a system of equations \mathbf{y} = \mathbf{A}\mathbf{c} where the entries in \mathbf{c} are small (say, K=10 elements) and the number equations (i.e., elements in \mathbf{y}) is huge (say, N=10000 elements).

I want to solve now for \mathbf{c}; this can be done using LS with the Pseudo inverse:

\mathbf{c} = \mathbf{A}^{\dagger} \mathbf{y}

However, the vector \mathbf{y} is now heavily corrupted by noise (just assume iid Gaussian).

I could calculate the mean over M consecutive elements in \mathbf{y} and rows in \mathbf{A} in order to average over the noise. The system would be collapsed to a smaller system with N/M entries which would be solved via LS.

Now I ask the question: Is this better than directly using LS with the full system?

I doubt because that's the sense of LS. However, I was not able to "proof" this analytically.

Any help?
Thanks,
 
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Hey divB.

Can you use the properties of a psuedo-inverse to show that this holds? (Recall that a pseudo-inverse has the property that C*C'*C = C)
 
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