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I am trying to work out a series expansion for ln ((x+1)/(x-1)).

I have got the series expansion for ln(x+1) ie x- (x^2/2) + (x^3/3) - (x^4/4) ...

and for ln(x-1) -x- (x^2/2) - (x^3/3) - (x^4/4) ...

Can I tie these two together to get the series for ln ((x+1)/(x-1)).

Or do I treat this as a new series.

regards

Brendan

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# Maclaurin series expansion

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