Magnetic Field and Electric field outside a long solenoid

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SUMMARY

The discussion focuses on calculating the induced electric field inside and outside a long solenoid with n turns per unit length carrying a time-varying current I=I₀sinωt. For the region inside the solenoid (rR), the induced electric field is E=-(μnIω(R²)cos(ωt))/(2r), which is not zero due to the changing magnetic flux despite the absence of a magnetic field outside the solenoid. This highlights the application of Faraday's Law in understanding induced electric fields.

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  • Understanding of Faraday's Law of Electromagnetic Induction
  • Familiarity with solenoid physics and magnetic fields
  • Knowledge of time-varying currents and their effects on electric and magnetic fields
  • Basic calculus for evaluating integrals related to electric fields
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  • Study the derivation of Faraday's Law and its applications in electromagnetic induction
  • Explore the behavior of magnetic fields inside and outside solenoids
  • Investigate the relationship between magnetic flux and induced electric fields in various geometries
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darkar
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Hello,

The question goes like this:

A long solenoid has n turns per unit length and carries a current given by I=I₀sinωt. The solenoid has a circular cross section of radius R. Find the induced electric field at a radios r from the axis of the solenoid for (a) r<R (b) r>R

Well, i got the first part as E=μR²N²ωI₀cos(ωt)/(2Rl). Does this looks like it?

For the second bit, i found it as zero. But i am not really sure. And if it is zero, What should i say?
 
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Hello there,

You'll have to excuse me because I'm not using the greek symbols.

(a) r<R,

int(E.dl)=-d(B.Area)/dt (definition of induced emf) take loop around

E.2*pi*r = -pi*(r^2)*mu*n*I*omega*cos(omega*t)

E= -(mu*n*I*omega*r*cos(omega*t))/2

is the induced field inside solenoid. Your answer is close but use r instead of R (since we are inside).

(b) r>R, outside

You are confusing with the case when magnetic field is zero outside long solenoid due to cancellations between field due to currents in successive & opposite loops.

In this case, (r>R...remember loop is longer)

E*2*pi*r = -pi*(R^2)*mu*n*I*omega*cos(omega*t)

(remember flux is over an area defined by pi*(R^2))

E = -(mu*n*I*omega*(R^2)*cos(omega*t))/ (2*r)

is the induced electric field outside.Hope that helps,
Rama
 
Last edited:
Are you sure they are asking about Electric fields? That doesn't make much sense. More often, you will be asked to solve for the magnetic field as a function of radius for the solenoid...
 
Yea, i m asked to find electric field. And i just found out this is one of the question found from the textbook. And yes, that's the correct answers! but i am still not sure why it is not zero. isn't that when there's no magnetic field, there's no electric field as well?
 
darkar,

To understand why there is an electric field outside the solenoid, just think about Faraday's Law. If you draw a loop around the solenoid, the magnetic flux through the loop is changing as a function of time, right? Even though there is no magnetic field outside the solenoid there is still a changing magnetic flux (from the field inside the solenoid). What does this tell you about the electric field?
 
Yea, that's amaze me. Why can there be magnetic flux but no magnetic field. So lif there's magnetic field, the magnetic flux is constant?
 

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