Magnetic field between two wires (vector sums)

AI Thread Summary
To find the magnetic field halfway between two parallel wires carrying currents I and 2I in opposite directions, the magnetic fields generated by each wire must be calculated using Ampere's law. The confusion arises from understanding how to combine the magnetic field vectors, as Ampere's law applies to the current enclosed by a loop. While the law describes the magnetic field at a point based on the enclosed current, the fields from both wires can still be added vectorially at the midpoint. The key is recognizing that the magnetic field contributions from each wire can be treated independently before summing them. This conceptual understanding is crucial for accurately determining the net magnetic field in the given scenario.
quantum13
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Homework Statement


Two parallel wires carry a current I and 2I in different directions. What is the magnetic field halfway between the two wires?


Homework Equations


Ampere's law
Int (B dot dA) = permissivity x enclosed current

The Attempt at a Solution


Draw a circle around wire 1
B x 2 pi r = mu x I
B = mu x I / 2 pi r
if d = distance between two wires, r = d/2


Where I'm confused is at the part where I add the two B vectors to find the total B. According to the rule of vector addition, I can add vectors to find the net vector. BUT I thought Ampere's law was supposed to describe all of the B at a point as proportional to ONLY the current inside and that currents outside the Amperian loop were not supposed to make any net contribution to B. So how can I add together two vectors when Ampere's law is supposed to describe a magnetic field with all the B vectors already added up? This is a more conceptual question. Thanks.
 
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Hi quantum13! :smile:

(have a mu: µ and a pi: π and btw, it's permeability for magnetism :wink:)
quantum13 said:
BUT I thought Ampere's law was supposed to describe all of the B at a point as proportional to ONLY the current inside and that currents outside the Amperian loop were not supposed to make any net contribution to B. So how can I add together two vectors when Ampere's law is supposed to describe a magnetic field with all the B vectors already added up? This is a more conceptual question. Thanks.

You have to look at the whole loop.

A loop C around a wire with currrent I1 and field B1 has an integral of ∫C B1.dl = 2πrB1 = µ0I1.

The same loop has an integral of ∫C B2.dl for a different wire, but B2 will not be constant, and if this wire lies outside C, the integral is zero. :wink:
 
hooray another annoying and difficult realization in the land of physics :)


thanks
 
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