Magnetic field created by a wire acts on the wire itself?

AI Thread Summary
The discussion centers on the magnetic field generated by a wire carrying current and its interaction with itself. Participants clarify that when calculating the total magnetic field on segment BA, the internal magnetic fields generated by other segments, such as CD, are typically not included in the calculations. This is because these internal forces do not affect the net force on the entire loop ABCD. The exercise's answer for the magnetic force on AB does not account for the magnetic field produced by BC, leading to a potentially incorrect result. Overall, the consensus is that while a wire does generate a magnetic field, it is often excluded from such calculations.
physics user1
So here is the problem, it asks me to find the total magnetic field on BA, i made a vectorial sum with the magnetic field generated by i1 and by i2 and i got the right result, but why not adding also the magnetic field generated by the wire itself? I mean generated by CD why isn't that correct? There is current i glowing in CD too, so it generates a magnetic field, why doesn't this add too? Basically I am asking: does a wire carriyng current generate a magnetic field that can imteract with that wire?
Please help me
 

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You are correct. The exercise doesn't take these 'internal' forces into account because they don't influence the net force on the complete loop ABCD.
 
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BvU said:
You are correct. The exercise doesn't take these 'internal' forces into account because they don't influence the net force on the complete loop ABCD.
So... if it asks me the total magnetic field on BA and doesn't take under account the field generated by CD the book gave me a wrong result? Thanks
 
I agree. It asks for the total magnetic force on AB and for the total force on CD. The 75.6 ##\mu##T in the answer for AB ignores the field produced by BC (88.4 ##\mu##T)
 
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