Magnetic Field Strength (Integral needed)

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SUMMARY

The discussion centers on calculating the magnetic field strength inside a solenoid constructed from 10 m of 0.55 mm diameter copper wire, with a current of 13 A. The relevant formula for magnetic field strength (B) is provided, incorporating the permeability constant (μ = 4π × 10^-7) and the number of turns in the solenoid. The initial calculation yielded B = 0.27 T, which was identified as incorrect, prompting a discussion on the necessity of integration versus using the standard solenoid formula.

PREREQUISITES
  • Understanding of solenoid physics and magnetic fields
  • Familiarity with the formula for magnetic field strength in solenoids
  • Knowledge of integration techniques in physics
  • Basic electrical concepts, including current and resistance
NEXT STEPS
  • Review the formula for magnetic field strength in a solenoid: B = μ * (N * I) / L
  • Study the derivation of the magnetic field inside a solenoid
  • Learn about the impact of wire diameter on solenoid performance
  • Explore integration techniques relevant to magnetic field calculations
USEFUL FOR

Students studying electromagnetism, physics educators, and anyone involved in electrical engineering or magnetic field applications.

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Homework Statement



You have 10 m of 0.55 mm diameter copper wire and a battery capable of passing 13 A through the wire. What magnetic field strength could you obtain inside a 2.8 cm diameter solenoid wound with the wire as closely spaced as possible?

Homework Equations



Turns of a solenoid = length of wire/ (2[tex]\pi[/tex] * radius of solenoid)

B = ( [tex]\mu[/tex]*turns of a solenoid * Current)/([tex]\sqrt{}(4(radius of solenoid)^2+(radius of copper wire)^2[/tex] where [tex]\mu = 4\pi *10^-7[/tex]

I believe that's right once you do the integration

The Attempt at a Solution



I tried to solve this and I got B = 0.27 T but it isn't right! I've tried over and over again, but I can't see to get the right answer.


Thanks!
 
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Why do you need integration? Can't you use the formula for the magnetic field inside a solenoid?
 
Well...you could be right. How would you do that?
 

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