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Magnetic Field Strength (Integral needed)

  • Thread starter smellsey
  • Start date
  • #1
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Homework Statement



You have 10 m of 0.55 mm diameter copper wire and a battery capable of passing 13 A through the wire. What magnetic field strength could you obtain inside a 2.8 cm diameter solenoid wound with the wire as closely spaced as possible?

Homework Equations



Turns of a solenoid = length of wire/ (2[tex]\pi[/tex] * radius of solenoid)

B = ( [tex]\mu[/tex]*turns of a solenoid * Current)/([tex]\sqrt{}(4(radius of solenoid)^2+(radius of copper wire)^2[/tex] where [tex]\mu = 4\pi *10^-7[/tex]

I believe thats right once you do the integration

The Attempt at a Solution



I tried to solve this and I got B = 0.27 T but it isn't right! I've tried over and over again, but I can't see to get the right answer.


Thanks!

Homework Statement





Homework Equations





The Attempt at a Solution

 

Answers and Replies

  • #2
ideasrule
Homework Helper
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Why do you need integration? Can't you use the formula for the magnetic field inside a solenoid?
 
  • #3
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Well...you could be right. How would you do that?
 

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