- #1

- 2

- 0

## Homework Statement

You have 10 m of 0.55 mm diameter copper wire and a battery capable of passing 13 A through the wire. What magnetic field strength could you obtain inside a 2.8 cm diameter solenoid wound with the wire as closely spaced as possible?

## Homework Equations

Turns of a solenoid = length of wire/ (2[tex]\pi[/tex] * radius of solenoid)

B = ( [tex]\mu[/tex]*turns of a solenoid * Current)/([tex]\sqrt{}(4(radius of solenoid)^2+(radius of copper wire)^2[/tex] where [tex]\mu = 4\pi *10^-7[/tex]

I believe thats right once you do the integration

## The Attempt at a Solution

I tried to solve this and I got B = 0.27 T but it isn't right! I've tried over and over again, but I can't see to get the right answer.

Thanks!