# Magnetic Flux and Induced Voltage Interesing question

## Homework Statement

assuming that friction is negligible and tthat electromagnetic forces are constant, (when they occur) calculate the speed of the cart at point 5w

this is part IV of a question, so in the other parts and in the given, i found out that:

mass of the cart=0.5kg
number of loops=150
hieght of the rampo=0.4m
height of the wire=0.1
width=0.2m
Resistance: 2.5 ohms
Magnetic field=1.2T

## Homework Equations

$\phi$=BA
$\epsilon$=-N$\Delta\phi$/$\Delta$t

## The Attempt at a Solution

The velocity of the cart at the bottom of the ramp is 2.8m/s
the Voltage of the cart as it enters the field is 50V
the current induced is 20A
The force of teh cart as it enters the field is 2.4N, making its acceleration 4.8m/s/s

Normal kinematics don't seem to work well, any tip?

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Simon Bridge
Homework Helper
What does "5w" refer to?
What is the geometry of the system?

You have not actually shown us how you attempted the problem - only the numbers you got as a result.

What does "5w" refer to?
What is the geometry of the system?

You have not actually shown us how you attempted the problem - only the numbers you got as a result.
5w refers to 5(.2)=1m

what i did was the following:

The acceleration is 4.8m/s/s, this is sort of like a railgun.

so

and i plugged in the humbers

V22=(2.8)2+2(4.8)(1)

and it turns out that supposedly v2=4.18

when it's supposed to be 2

so now this makes me think why this isn't exactly like a railgun (the velocity decrased)

any ideas?

for some reason I think this can only be solved with calculus, just a feeling, a weird feeling though...

Simon Bridge