Magnetic Flux and Induced Voltage Interesing question

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Homework Help Overview

The discussion revolves around calculating the speed of a cart at a specific point in a system influenced by magnetic forces. The context includes parameters such as mass, number of loops, ramp height, wire height, width, resistance, and magnetic field strength.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants explore the relationship between the cart's speed and the effects of magnetic forces, questioning the assumptions made about the system's geometry and forces involved. There is a mention of using kinematic equations and a comparison to a railgun setup.

Discussion Status

Participants are actively questioning the setup and the assumptions regarding the geometry of the system. Some guidance has been offered regarding the effects of the magnetic field on the cart's speed, but there is no explicit consensus on the approach to take.

Contextual Notes

There is a noted uncertainty about the geometry of the system, specifically regarding the slope and how it interacts with the magnetic field. Participants express a feeling that calculus may be necessary to fully resolve the problem.

stonecoldgen
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Homework Statement


assuming that friction is negligible and tthat electromagnetic forces are constant, (when they occur) calculate the speed of the cart at point 5w

this is part IV of a question, so in the other parts and in the given, i found out that:

mass of the cart=0.5kg
number of loops=150
hieght of the rampo=0.4m
height of the wire=0.1
width=0.2m
Resistance: 2.5 ohms
Magnetic field=1.2T



Homework Equations



[itex]\phi[/itex]=BA
[itex]\epsilon[/itex]=-N[itex]\Delta\phi[/itex]/[itex]\Delta[/itex]t


The Attempt at a Solution


The velocity of the cart at the bottom of the ramp is 2.8m/s
the Voltage of the cart as it enters the field is 50V
the current induced is 20A
The force of the cart as it enters the field is 2.4N, making its acceleration 4.8m/s/s


Normal kinematics don't seem to work well, any tip?
 
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What does "5w" refer to?
What is the geometry of the system?

You have not actually shown us how you attempted the problem - only the numbers you got as a result.
 
Simon Bridge said:
What does "5w" refer to?
What is the geometry of the system?

You have not actually shown us how you attempted the problem - only the numbers you got as a result.

5w refers to 5(.2)=1m

what i did was the following:

The acceleration is 4.8m/s/s, this is sort of like a railgun.

so

V22=v12+2ad

and i plugged in the humbers

V22=(2.8)2+2(4.8)(1)

and it turns out that supposedly v2=4.18

when it's supposed to be 2



so now this makes me think why this isn't exactly like a railgun (the velocity decrased)

any ideas?




for some reason I think this can only be solved with calculus, just a feeling, a weird feeling though...
 
This is why I asked about the geometry - isn't there a slope involved?
 
Simon Bridge said:
This is why I asked about the geometry - isn't there a slope involved?

There is a slope and then comes the magnetic field. The magnetic field lies on a flat surface. I already calculated the speed the cart gets when it reaches the flat part.
 
OK - so if your initial speed is 2.8m/s, and the final speed is supposed to be 2m/s, then what is the effect of the magnetic field on the cart?
 

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