Magnetic flux through a solenoid

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SUMMARY

The discussion centers on the calculation of magnetic flux through a solenoid, specifically addressing the formula for flux as BA and the confusion surrounding the use of the number of turns per unit length (n) and the length of the solenoid (L). The participants clarify that the magnetic flux through a single loop is given by the formula nμI, leading to the total flux for the solenoid being nL multiplied by the flux of a single loop. The confusion arises from the distinction between the number of turns (N) and the turns per unit length (n), with the conclusion that N is derived from multiplying n by L.

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quietrain
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ok, the magnetic field through a single ring is n\muI ,
so the flux is BAcos(theta), with cos(theta)=1, flux = BA = piR2n\muI

so why for the entire solenoid flux, it is now nL*the flux above? where L = length of solenoid

shouldn't multiplying it with just n = number of rings be suffice?

also, i don't really understand the magnetic flux. is it define to be the number of field lines per unit area? it is something like density right? so shouldn't it be flux = B/A ? i am getting confused :X

thanks
 
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Those formulas look pretty wrong. The flux should decrease with the length of the coil. And your first formula contains a number n that is not even defined for a single loop (or simply n=1)

Maybe this helps: http://en.wikipedia.org/wiki/Solenoid
 
yup, for a single coil , n = 1.

but i don't understand why for the entire solenoid, we use n*L*dflux/dt = induced EMF

shouldn't just multiplying with n be enough? because n = number of turns. and dflux/dt is for 1 turn. so the entire solenoid just needs to be multiplied by n turns. why do we multiply another length L factor? it is taken from masterphysics.com
 
oh i realize where it all went wrong. after reading the question again for the 3000 time, i realize that n was the number of turns per unit length. so to get N, number of turns, we have to multiply n with L. -.-

sorry for the commotion
 

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