Magnetic force on a current carrying wire

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The formula for the force on a current-carrying wire, F=BIL, considers the magnetic field strength (B) at the location of the wire and the length of the wire (L) but does not explicitly include the distance from the magnet. The magnetic field strength decreases with distance, meaning a wire farther from the magnet experiences a weaker force due to a weaker magnetic field. The formula assumes a uniform magnetic field along the wire's length, which is often not the case in practical scenarios. Demonstrations typically use bar or horseshoe magnets to create a more uniform field in the relevant area. Understanding the local magnetic field is crucial for accurate calculations of the force on the wire.
pantheid
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Hi, I am slightly confused by the formula for finding the force on a current carrying wire. It is given as F=BIL where F is force, B is the strength of the magnetic field and L is the length of the wire being acted upon. What I don't understand is why this formula doesn't factor in the distance between the magnet and the wire itself.
 
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pantheid said:
Hi, I am slightly confused by the formula for finding the force on a current carrying wire. It is given as F=BIL where F is force, B is the strength of the magnetic field and L is the length of the wire being acted upon. What I don't understand is why this formula doesn't factor in the distance between the magnet and the wire itself.

The magnetic field B is taken to be the field present at the wire itself. Any position dependence of B must be known in order to know the field at the wire. So, yes a far aways magnet will have less force on the wire, but it will also present less magnetic field to the wire. You would not want to use the value of B near the magnet in the calculation of force on a wire a long distance away.

Note that this formula is a simplification that assumes the magnetic field is uniform over the entire length of the wire, which is not likely to be true for a real magnet and a wire of any appreciable length.
 
The usual arrangement for demonstrating this involves using a pair of bar magnets (using the gap between a N and opposing S pole), or else a horseshoe magnet, and this arrangement makes the field in that region approximately uniform.
 
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