Modey3 said:
Hello. I'm still confused about the thermodynamics involved in magnetic domain wall motion. I understand the different pinning mechanisms, but I fail to see how this phenomena leads to Irreversible losses during magnetic hysterisis. For instance, how can precipitate which can put a section of a domain wall in an "energy well" lead to irreversible losses. I'm sure the answer is really simple, but at this moment I'm not seeing it. Is there a mechanical anaology? Thanks
Modey3
All that follows is what I've just thought through, so take it as nothing more than my opinion (though, one that I feel reasonably confident in).
The key is in the difference between the driving forces for domain wall motion during magnetization and demagnetization. During magnetization, the driving force is the applied field, H. As the domain wall passes a "particle" it falls into a potential well. Increasing H eventually provides sufficient energy to raise it out of the well and continue moving it. During demagnetization, the driving force is actually thermal excitations at ambient temperature (and spin-spin interactions, which are small enough to neglect, for this discussion).
Consider a magnetized sample with one part of a domain wall pinned at a particle in some applied field +H. Increasing the field will move the wall beyond this particle, but let's stop at this particular value of the field, and instead of increasing it, simply turn off the field. Now the probability that the wall gets unpinned depends on the the temperature. At low temperatures, thermal excitations may not be enough to unpin the wall, but at high temperatures they may be. So, if thermal excitation is insufficient tp unpin the wall, it will take an extra reverse field (the coercive field, Hc) of sufficient strength to achieve this unpinning. So, extra work needs to be cone to bring the domain wall back to its original position (or the sample back to zero magnetization).
This extra energy is the hysteretic loss per cycle.
Note : It is a natural conclusion from this, that if at ambient temperature, kT >> U(particle), there will be essentially no hysteresis. On the other extreme, at 0K, hysteresis should be "perfect" and the M-H curve must look like a rectangular box. I'm a little rusty on this but I believe these are consistent with experiment, where Hc decreases with increasing T (< Tc).
PS : Forgive the sloppy figure.
