Magnetron Electron Field Strength

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SUMMARY

The discussion focuses on calculating the strength of the magnetic field (B) for an electron with a resonant frequency of f = 1.47×1010 s−1 and a period of revolution T = 6.80×10−11 s. The relevant equations used include qvb = mv2/r and qb = mv/r. By determining the velocity (v) as a function of radius (r) using the relationship v = 2πR/T, the magnetic field strength is calculated to be B = 0.5253 T. This calculation is crucial for understanding the behavior of electrons in magnetic fields.

PREREQUISITES
  • Understanding of classical mechanics, specifically circular motion
  • Familiarity with electromagnetic theory, particularly Lorentz force
  • Knowledge of the relationship between frequency, period, and velocity
  • Basic algebra skills for manipulating equations
NEXT STEPS
  • Study the derivation of the Lorentz force equation qvb = mv2/r
  • Learn about the implications of magnetic fields on charged particles in motion
  • Explore the concept of cyclotron frequency and its applications
  • Investigate the effects of varying magnetic field strengths on electron trajectories
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Students studying electromagnetism, physicists interested in particle dynamics, and educators seeking to explain the principles of magnetic fields and electron behavior.

haxxorboi
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Homework Statement


Suppose the resonant frequency is f = 1.47×1010 s−1; that is, the electron period of revolution is T = 6.80×10-11 s. What is the corresponding strength of the magnetic field?


Homework Equations


qvb=mv2/r
qb=mv/r


The Attempt at a Solution


1.6E-19*b=9.1E-31*v/r

I understand the general idea, to figure out b, but I don't understand how to figure out Velocity or Radius from the frequency/period.

Can someone give me a point in the right direction?
 
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Hi haxxorboi,

haxxorboi said:

Homework Statement


Suppose the resonant frequency is f = 1.47×1010 s−1; that is, the electron period of revolution is T = 6.80×10-11 s. What is the corresponding strength of the magnetic field?


Homework Equations


qvb=mv2/r
qb=mv/r


The Attempt at a Solution


1.6E-19*b=9.1E-31*v/r

I understand the general idea, to figure out b, but I don't understand how to figure out Velocity or Radius from the frequency/period.

When they give the period, that is the period of what? In other words, if the period is 6.80×10-11 s, what happens every 6.80×10-11 seconds? Once you answer that, you should be able to write down an equation relating T, r, and v. What do you get?
 
alphysicist said:
Hi haxxorboi,

When they give the period, that is the period of what? In other words, if the period is 6.80×10-11 s, what happens every 6.80×10-11 seconds? Once you answer that, you should be able to write down an equation relating T, r, and v. What do you get?

Velocity=Distance/Time
Velocity=Circumference/Period
Velocity=2*Pi*R/6.8E-11 sec
Velocity=9.24E10R

1.6E-19*B=9.1E-31*(9.24E10R)/R

B=.5253 T


Thank you very much, that was killing me!
 

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