# Magnitude and direction of velocity

1. Aug 4, 2006

### prabhjyot

The end A of the link in a guide has a constant downward velocity of 3 m/s as shown in the diagram. For the instant where the link AB makes an angle of 75 degrees with the vertical guide calculate the magnitude and direction of the velocity of the roller at B, the magnitude and direction of velocity of the centre of the link AB and the angular velocity of the link AB. Is the velocity at B also constant?

File size:
1.7 KB
Views:
46
2. Aug 5, 2006

### HallsofIvy

Staff Emeritus
That looks like a typical Calculus "related rates" problem!

You need two formulas: by the Pythagorean theorem, a2+ b2= 2002, where b is the distance from B to the corner and a is the distance from A to the corner. Differentiate that formula with respect to time (using the chain rule, of course) to determine db/dt (you are given da/dt), the "magnitude of the velocity of the roller at B". The direction should be obvious.

You also have $cos(\theta)= \frac{a}{200}$ where $\theta$ is the angle AB makes with the vertical guide (75 degrees at the instant in question). Differentiate that to determine "the angular velocity of the line AB", $\frac{d\theta}{dt}$.

For the midpoint, you can do the same thing but use 100 mm instead of 200.