Magnitude & Direction of Electric field

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SUMMARY

The discussion focuses on calculating the magnitude and direction of the electric field required to balance the weight of an electron and a proton. The weight of an electron is approximately 9.81 x 10-31 kg and for a proton, it is about 1.67 x 10-27 kg. To achieve equilibrium, the electric force exerted on each particle by the electric field must equal their respective weights. This can be determined using the formula F = qE, where F is the force, q is the charge, and E is the electric field strength.

PREREQUISITES
  • Understanding of electric fields and forces
  • Knowledge of basic physics concepts such as weight and mass
  • Familiarity with the formula F = qE
  • Ability to draw and interpret force diagrams
NEXT STEPS
  • Calculate the electric field strength required to balance the weight of an electron using F = qE
  • Calculate the electric field strength required to balance the weight of a proton using F = qE
  • Explore the concept of force diagrams in physics for better visualization
  • Review the properties of electric charges and their interactions with electric fields
USEFUL FOR

Students studying physics, educators teaching electric fields, and anyone interested in understanding the balance of forces acting on charged particles.

Ahsan123
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What are the magnitude and direction of the electric field that will balance the weight of (a) an electron and
(b) a proton?

Please I am getting confused in this question. I want help with complete explanation. Thanks in advance. How will it done..?
 
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Do you have any ideas where to start?

Some hints: 1) draw a force diagram, it should just have 2 forces. 2) what is the weight of an electron/proton, and how are they affected by an electric field? (i.e. what force is exerted on them by an electric field?)
 

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