Magnitude of an electric field at two points

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SUMMARY

The discussion centers on comparing the magnitudes of electric fields at two points, A and B, in relation to their proximity to a charge. The correct conclusion is that the electric field strength at point A is greater than at point B due to the inverse square law governing electric fields. The participant initially assumed proximity to the charge directly correlated with field strength but learned that field strength is also influenced by the distribution of field lines in the diagram provided.

PREREQUISITES
  • Understanding of electric fields and their properties
  • Familiarity with Coulomb's Law
  • Knowledge of field line diagrams and their interpretation
  • Basic grasp of vector quantities in physics
NEXT STEPS
  • Study the inverse square law as it applies to electric fields
  • Learn how to interpret electric field line diagrams
  • Explore Coulomb's Law and its applications in electric field calculations
  • Examine the concept of electric field strength and its mathematical representation
USEFUL FOR

Students studying electromagnetism, physics educators, and anyone seeking to deepen their understanding of electric field concepts and their applications in real-world scenarios.

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Homework Statement


Compare the magnitude of the electric field at position A with the magnitude of the electric field at position B.

A) E-Field Magnitude at Point A > E-Field Magnitude at Point B
B) E-Field Magnitude at Point A = E-Field Magnitude at Point B
C) E-Field Magnitude at Point A < E-Field Magnitude at Point B

Homework Equations



The Electric Field:
http://imageshack.us/f/407/efield.jpg/


The Attempt at a Solution



I thought the electric field at A would be stronger because its closer to the charge causing the field, but I got it marked wrong. Can someone explain to me what is the correct answer?
 
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On these types of diagram, what indicates the strength of the electric field?
 

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