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Magnitude of electric field - Problem check

  1. Aug 29, 2006 #1
    Hey everyone. I've been getting tons of help on here and it's paying off. I really appreciate your efforts. Could someone check this problem for me and tell me if I have the right answer?

    Book: Cutnell & Johnson Physics
    pp. 571 #66

    A small object, which has a charge q = 7.5uC and mass m = 9.0 x 10^-5kg, is placed in a constant electric field. Starting from rest, the object accelerates to a speed of 2.0 x 10^3m/s in a time of 0.96 s. Determine the magnitude of the electric field.

    My Answer:

    I found the equation for the magnitude of an electric field: E= k|q| / r^2

    I wasn't sure how to find r but I noticed I had a and t so I did the following: r = (2.0 x 10^5) x (9.6)^2 / 2 = 1.8 x 10^8

    I did that because, in order to find the time you do sqrt{2(distance)/(accel)} correct?

    Then I did E = (8.99 x 10^9) x (7.5 x 10^-6) / (1.8 x 10^8)^2 = 2.08 x 10^-12

    I figure if I messed up it's probably doing the reverse acceleration equation. Can someone check for me? Thanks! :rofl:
  2. jcsd
  3. Aug 29, 2006 #2


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    No, you cannot use this equation here. The E field is uniform which tells you that it is *not* produced by a point charge. It is produced by a large uniformly charged surface or some other charge distribution. The only thing you can use then is F=q E.
    So you must use the information about the motion to find the acceleration, then use F=m a to find the force and then use F=qE to find the magnitude of the E field.

    I did that because, in order to find the time you do sqrt{2(distance)/(accel)} correct?
    Yes (if an onbject starts from rest and moves along a straight line) BUT you do not know the acceleration here! Just the final speed!
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