(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Two charges, +q and -q, are located in the x-y plane at points (0,+d/2) and (0,-d/2), respectively. Calculate the magnitude of the electric field at point P with the superposition principle.

Data: q=37.0 nanoCoulombs,

d=4.60mm and P at

x=92.0mm.

2. Relevant equations

E = kQ/r^2

a^2 + b^2 = c^2

sin = o/h

3. The attempt at a solution

I tried to solve this like a normal E field question.

For the +q charge, I got that the E field would be:

( k * -37E-6 (sin2) / .092^2) + ( k * 37E-6 (cos2)

and For the -q charge, I got that the E field would be:

( ( k * -37E-6 (sin2) / .092^2) - ( k * 37E-6 (cos2)

This came out to 2740 N/C (positive b/c it asks for magnitude) but that was wrong. Can someone tell me where I'm going wrong? I attached the diagram.

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# Homework Help: Magnitude of Electric field using superposition principle

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