1. May 18, 2008 #1

   jostpuur

   

   I just encountered a claim, that for any given metric space (X,d), there exists another topologically equivalent metric d' so that (X,d') is bounded. Anyone knowing anything about the proof for this?

    

   jostpuur, May 18, 2008
2. 
   Phys.org - latest science and technology news stories on Phys.org

   • • Game over? Computer beats human champ in ancient Chinese game
   • • Simplifying solar cells with a new mix of materials
   • • Imaged 'jets' reveal cerium's post-shock inner strength
3. May 18, 2008 #2

   morphism

   

   Science Advisor

   Homework Helper

   Try putting d'=d/(1+d) or min{1,d}.

    

   morphism, May 18, 2008
4. May 18, 2008 #3

   jostpuur

   

   Ok. I checked the min{1,d} one.

    

   jostpuur, May 18, 2008

• Log in with Facebook
• Log in with Twitter

Your name or email address:

Do you already have an account?

• No, create an account now.
• Yes, my password is:
• Forgot your password?

Stay logged in