1. May 18, 2008 #1

   jostpuur

   

   I just encountered a claim, that for any given metric space (X,d), there exists another topologically equivalent metric d' so that (X,d') is bounded. Anyone knowing anything about the proof for this?

    

   jostpuur, May 18, 2008
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3. May 18, 2008 #2

   morphism

   

   Science Advisor

   Homework Helper

   Try putting d'=d/(1+d) or min{1,d}.

    

   morphism, May 18, 2008
4. May 18, 2008 #3

   jostpuur

   

   Ok. I checked the min{1,d} one.

    

   jostpuur, May 18, 2008

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