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Making given metric space bounded

  1. May 18, 2008 #1
    I just encountered a claim, that for any given metric space (X,d), there exists another topologically equivalent metric d' so that (X,d') is bounded. Anyone knowing anything about the proof for this?
  2. jcsd
  3. May 18, 2008 #2


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    Try putting d'=d/(1+d) or min{1,d}.
  4. May 18, 2008 #3
    Ok. I checked the min{1,d} one.
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