Mass added to a spring to increase period of oscillation

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SUMMARY

The discussion centers on determining the mass required to double the period of oscillation for a mass-spring system. The relevant formula is T = 2π√(m/k), where T is the period, m is the mass, and k is the spring constant. To achieve a period that is twice the original, the total mass must increase to 4m, resulting in an additional mass of 3m. This conclusion is derived from the relationship between the period and mass, confirming that the correct answer is 3m.

PREREQUISITES
  • Understanding of harmonic motion and oscillation principles
  • Familiarity with Hooke's Law (f = -kx)
  • Knowledge of the formula for the period of a mass-spring system (T = 2π√(m/k))
  • Basic algebra skills for manipulating equations
NEXT STEPS
  • Study the derivation of the period formula for mass-spring systems
  • Explore the effects of varying spring constants on oscillation periods
  • Learn about energy conservation in oscillating systems
  • Investigate real-world applications of harmonic motion in engineering
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Students studying physics, particularly those focusing on mechanics and oscillatory motion, as well as educators seeking to clarify concepts related to mass-spring systems.

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Homework Statement



7. Mass m is oscillating on the end of a spring. How much mass must be added in order for the
period of oscillation to increase by a factor of two?
A.m
B.2m
C.3m
D.4m
E.8m

Homework Equations



f=-kx
w= \sqrt{k/m}
T = 2\pi\sqrt{m/k}

The Attempt at a Solution



since period (T) is proportional to the square root of m and we want 2t, i had 2T=\sqrt{m} so 2^2 =4

the given answer is 3 and i don't know how this was chosen
 
Physics news on Phys.org
You found the factor by which the total mass has to increase. But what do they ask for?
 
yeah that makes sense haha 4xm =4m - m that i started with is 3m
thanks a lot it was blowing my mind
 

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