Mass and velocity, thank you for your help

UglyNakedGuy
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Dear all,

I am a lover in astrophyics, however, I have not got much knowledge in it. Recently, I read a book and it says " the mass (of an object) increases as its velocity goes up", I don't think my brain works for this sentence...

I seem to remember that P=M*V, so literally, if velocity increases mass should decrease?

Please don't laugh and enlighten me :P
 
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p=m*v is from Newtonian mechanics whereas the statement on increasing mass with increasing speed is related to special relativity theory and applicable for speeds approaching the speed of light.
 
so may I know the equation for p under SR? thank you for your reply :)
 
This is the concept of "relativistic mass" which was once quite popular but rarely used nowadays amongst professional physicists, who prefer to stick with a non-varying "rest mass".

I hope you are familiar with the concept of kinetic energy -- "the energy (of an object) increases as its velocity goes up" -- and also with E = mc2 relating mass to energy. The idea of relativistic mass was to treat kinetic energy as part of an object's mass
 
In relativity we have momentum p and energy E given by\begin{align}<br /> \textbf{p} &amp;= \frac{m\textbf{v}}{\sqrt{1-v^2/c^2}} \\<br /> E &amp;= \frac{mc^2}{\sqrt{1-v^2/c^2}}<br /> \end{align}where m is rest mass. Relativistic mass was<br /> \frac{m}{\sqrt{1-v^2/c^2}}<br />
 
DrGreg said:
This is the concept of "relativistic mass" which was once quite popular but rarely used nowadays amongst professional physicists, who prefer to stick with a non-varying "rest mass".

I hope you are familiar with the concept of kinetic energy -- "the energy (of an object) increases as its velocity goes up" -- and also with E = mc2 relating mass to energy. The idea of relativistic mass was to treat kinetic energy as part of an object's mass

I see, so that's actually a algebra thing?

(for my own understanding , sorry if I am wrong) the energy of an object and its V have a positive correlation, so E goes up when speed goes up.

and then, since E=mc^2, and c is constant ( assume in vaccum) so we relate E with c .

is this correct?

thank you !
 
if you set v=0 then you get the famous e=mc^2, the energy at rest from the equations above.
 
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