autodidude said:
@ cepheid:
EDIT 1:I'm just talking about scales on Earth :p
EDIT 2: Yes, that's what pretty much what I wanted to know, whether the scale was calibrated to find your mass or not
Well that's the thing.
Scales measure weight, so they'll always tell you your correct weight no matter
where you are. In contrast, they can only tell you your mass correctly if you're on Earth. Elsewhere, the calibration breaks down and has to be redone.
autodidude said:
EDIT 3: So say. 70kg, you'd have to convert that?
I was pointing out a subtlety. If you have a mass of 70 kg, then on Earth you'll weigh approx. 687 Newtons (N), or 154 lbs in Imperial units. If you then went to the moon (where surface gravity is only about 1/6 as strong), and stood on the scale, the dial would read 70/6 kg = 11.67 kg. Clearly, if you interpret this as your mass, it is just plain WRONG. Your mass is 70 kg,
not 11.67 kg. This illustrates that scales measure weight, not mass. But here is the subtlety: there is a unit of force called the kilogram-force (kgf) which is defined as the weight that a mass of 1 kg would have in the standard Earth gravitational field of g = 9.81 N/kg. In other words, 1 kgf = (1 kg)*g = 9.81 N. Now, let's take your weight on the moon (687/6 N = 114.5 N) and convert that into kgf: 114.5 N * (1 kgf/9.81 N) = 11.67 kgf.
So, IF you interpret the kg numbers on the dial as being units of force (kgf) then they will always show you the correct value, since you're interpreting them as a measurement of weight. The same thing is true of the pounds (lbs) scale. If you interpret them as being pounds-mass (lbm) then the measurement is wrong everywhere except on the surface of the Earth. But if you interpret them as being pounds-force (lbf) then the reading is always correct.
By the way, I wouldn't recommend using kgf, since it's not a standard SI unit. Use Newtons as the units for expressing all forces (including weight). Using Newtons also helps make sure you distinguish between mass and weight clearly. Using kgf confuses things, since the mass and weight will have the same numerical value (on Earth).