ElmorshedyDr said:
I only understand mass and energy according to Newtonian mechanics,
Where mass is the resistance of a body to accelerate, or how much matter there is, and anything has mass is a matter.
Energy is the ability to do work and it's not a matter.
It was believed that mass and energy are two different separated things until Einstein who explained that they are the same thing, I don't understand how are they same thing, and what are their new conceptions according to Einstein and to special relativity.
I'm still a freshman in special relativity, so I barely know much about it, I'd like a simple intuitive explanation if possible, and thanks !
In Newtonian mechanics, "quantity of matter", "force required to accelerate", and mass are all the same thing.
In special relativity, they're three different things. This is probably the first lesson to learn.
The equations are not that complicated to present, and hopefully will lead to understanding of the testable, scientific issues. Note that we try to avoid extended discussion of the non-scientific, non-measurable philosophical issues here on PF, mainly because such issues tend to wind up in endless arguments with no clear resolution. This happens precisely because the issues can't be resolved by experiment.
Here are the details.
A point particle (or an isolated system that isn't a point) has a characteristic property, called its "mass", (more precisely, it's invariant mass) that is a property of the particle which is independent of the observer.
Momentum is a concept shared by Newtonian mechanics and relativity, though the formulae are different the ideas remain the same.
The momentum of such a particle is given by the expression p = ##\gamma m v## where ##\gamma = 1 / \sqrt{1-v^2/c^2}## where m is the invariant mass, and v is the velocity of the particle. Note the difference from Newtonian physics, which doesn't include the factor of ##\gamma##.
Force is the rate of change of momentum with time. This is true in both special relativity and Newtonian mechanics. One may or may not be used to describing force in this manner in Newtonian mechanics, but it becomes worthwhile to learn this because this definition works for special relativity too.
Using the chain rule from calculus we can write:
##F = dp/dt = (d/dt) (\gamma m v) = (d\gamma/dt) m v + \gamma (dm/dt) v + \gamma m (dv/dt)##
Thus F = ma no longer works in special relativity, so you need to disambiguate "mass" from "force required to accelerate", they're different concepts now. As you can see the force expression is complicated - forces are usually replaced with 4-fources for this reason, but at this point I feel a further explanation of this point would be more distracting then helpful.
Energy for a moving particle with velocity v in special relativity is given by the formula E = \gamma m c^2 This is different from the Newtonian formula in that the energy is not zero when the velocity is zero, it is instead given by mc^2. When you regard energy as the integral of work ##E = \int dW##, the change in the energy at zero velocity is just a change in the constant of integration.
However, if you have a particle of mass m, and an anti-particle of mass m, (neither of which is moving so there is no significant kinetic energy) and you annihilate them in a particle-anti-particle reaction, the released energy will be 2*m*c^2. Thus this simple additive constant does has some physical interpretation in keeping with the "ability to do work" paradigm, as includes the energy (ability to do work) available in the system via the mechanism of particle-antiparticle annihilation. This is more significant for particle physics than everyday physics, but the definition of the energy being equal to mc^2 at zero velocity in special relativity remains as the default choice even in non-particle physics applications.
This choice of energy = mc^2 at zero velocity is also necessary for the well-known equation
E^2 = (p c)^2 + (m c^2)^2 to work, E being the energy, p being the magnitude of the momentum, and m being the invariant mass.