Mass Spectrometry Homework: Determining Atomic Mass

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The discussion focuses on determining the atomic mass of a rarer carbon isotope using mass spectrometry data. The abundant isotope has an atomic mass of 12.0000 u and moves in a circle with a radius of 9.00 cm, while the rarer isotope has a radius of 9.36 cm. An initial calculation suggested the rarer isotope's mass is 12.48 u, but this was identified as incorrect due to a misunderstanding of the velocities of the ions. It was clarified that although both isotopes are accelerated through the same potential difference, they do not have the same velocity. The conversation emphasizes the importance of correctly applying the principles of mass spectrometry to solve for atomic masses.
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Homework Statement



Natural carbon consists of two different isotopes (excluding 14C, which is present in only trace amounts). The isotopes have different masses, which is due to different numbers of neutrons in the nucleus; however, the number of protons in the same, and subsequently the chemical properties are the same. The most abundant isotope has an atomic mass of 12.0000 u. When natural carbon is placed in a mass spectrometer, two lines are formed on the photographic plate. The lines show that the more abundant isotope moved in a circle of radius 9.00 cm, while the rarer isotope moved in a circle of radius 9.36 cm. What is the atomic mass of the rarer isotope? (The ions are accelerated through the same potential difference before entering the magnetic field.)

Homework Equations



r = mv^2 / qvB

The Attempt at a Solution



Charges, velocities, and magnetic fields are the same. Set up ratio:

radius abundant / radius rarer = mass abundant / mass rarer

9 cm / 9.36 cm = 12 u / x

x = 12.48 u

This answer shows as incorrect. Any thoughts? Thanks.
 
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azhoops said:

Homework Statement


(The ions are accelerated through the same potential difference before entering the magnetic field.)

If they are accelerated through the same potential difference they don't have the same velocity.
 
Thanks! I got it.
 
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