Mastering Equations: How to Graph x against t with Ease

  • Thread starter Thread starter romd
  • Start date Start date
AI Thread Summary
The discussion focuses on transforming the equation x(t)=e^(-t/tau) sin(omega*t) into a linear format suitable for graphing position (x) against time (t). Participants clarify that the original equation describes a damped oscillator, which inherently does not produce a straight line graph. Suggestions include using logarithmic transformations, although this may not apply due to the sine component. One participant proposes substituting the function into a linear equation format to find corresponding y values. The conversation highlights the complexity of the task and the need for a deeper understanding of mathematical transformations.
romd
Messages
7
Reaction score
0
Hi, I need help manipulating the equation

x(t)=e^(-t/tau) sin(omega*t)

into a straight line graph (y=mx+c) of position (x) against time (t)

Thanks in advance!

edit: this might have been better off in the homework/coursework section, sorry
 
Physics news on Phys.org
Do you mean x = m.t + c ?
Are you allowed to make co-ordinate transformations ? The equation describes a damped oscillator so there doesn't seem to be any other way.
 
Thanks for the reply!
Probably, I just know I need a straight line out of it.. I think its a little beyond my knowledge, given my college teacher has no idea either. Once I have the equation I'll be set.
 
The question is "make a straight line out of what"? The graph of the function you give, x(t)=e^{-t/\tau} sin(\omega t), in the "tx-plane" is certainly not a straight line and there is no y. The graph of that would be a "wave" getting smaller and smaller as t increases. Sometimes you can make a function into a linear graph by plotting the logarithms of the values rather than the values themselves, but that won't work with that "sin" there.

Perhaps you mean that, given this x value, as a function of t, find the corresponding y value on the line y= mx+ b. That's easy- just substitute that function for x:
y= me^{-t/\tau} sin(\omega t)+ b. The values given by those functions will give the position, at time t, of an object moving along the line y= mx+ b.
 
Back
Top