Image location and magnification for object at center of curvature of concave mirror

[leehom]

Use the mirror equation to find the image location and the height of an object placed at the centre of curvature of a concave mirror. Also find the magnification. Hint: What is the relation between the focal length and the object distance, do, for this situation?

I'm really confused about this question... Can someone please help me?

 

[Chi Meson]

What's the mirror equation? (It's the same as the thin-lens equation)

What's the relationship between the center of curvature and the focal point?

 

[leehom]

centre of curvature is half the focal point and the mirror equation is 1/di + 1/do = 1/f

 

[leehom]

but i still don't understand how that answers the question..

 

[Chi Meson]

I was answering your other thread.

Center of curvature is not half the focal length, it's the other way 'round.

Center of curvature is twice the focal length. So focal length is "f" and the object distance is "2f." Do a little algebra and find the image.

 

[leehom]

Would the focal length be equal to the object distance?

 

[Chi Meson]

Would the focal length be equal to the object distance?

No, try again. You're close.

But I have to go now, keep at it.

 

[leehom]

Okay, thnx for your help

 

[Kurdt]

All you have to do is substitute 2f = d_o into the equation you listed above and solve for d_i.