Krasz
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Krasz said:How did you get from step 2 to step 3? Such as how did 2x come into play?
arildno said:After step 1, we have the following "bottom part":
[tex]x+\frac{1}{\frac{x^{2}+x+1}{x+1}}=x+\frac{x+1}{x^{2}+x+1}[/tex]
Agreed thus far?
Now, we find a common denominator to the above sum:
[tex]x+\frac{x+1}{x^{2}+x+1}=\frac{x*(x^{2}+x+1)+x+1}{x^{2}+x+1}[/tex]
Calculate the numerator of this expression!