Mathematical description of a ball hitting a glass plate and causing damage

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Discussion Overview

The discussion revolves around the mathematical representation of damage caused to a glass plate by a ball impacting it. Participants explore concepts related to stress and strain tensors, yield stress, and the conditions under which glass may crack or break upon impact.

Discussion Character

  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant suggests using stress or strain tensors to mathematically represent the damage caused by a ball hitting a glass plate perpendicularly.
  • Another participant confirms the relevance of yield stress and ultimate stress in understanding material deformation and failure, particularly in brittle materials like glass.
  • A later reply discusses calculating the force on the glass plate based on the ball's velocity and converting it to kinetic energy, indicating that local contact stress may cause a crack without complete breakage.
  • Participants mention that the strength of glass is influenced by initial flaws, with a significant range of breaking strength depending on these flaws.

Areas of Agreement / Disagreement

Participants generally agree on the importance of yield stress and ultimate stress in the context of material failure, but there are varying interpretations of how these concepts apply specifically to the scenario of a ball impacting a glass plate. The discussion remains unresolved regarding the precise mathematical modeling of the damage.

Contextual Notes

There are limitations in the discussion regarding the assumptions made about the material properties of glass, the specific conditions of the impact, and the mathematical steps required to fully describe the damage. The discussion does not resolve these complexities.

mohammed El-Kady
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Summary: damage on glasses plate by hitting ball

If a ball hit a rectangular plate of glass and it cause a damage "but it didn't broken" how can i represent this damage using mathematics?
I'll tell you my idea about it: let the ball move horizontally and hit the plate perpendicularly with momentum mv then the damage will be described as stress or strain tensor. This my idea if it's wrong tell me the truth.
 
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You are correct that the stress and strain tensors are used to represent the material properties of materials. What you are probably interested in is the yield stress. At this point the material will begin to permanently deform. The ultimate stress would be the stress at which it breaks entirely. For materials like steel there is a fairly large difference between the yield stress and the ultimate stress, but for brittle materials like glass they are fairly close.
 
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Dale said:
You are correct that the stress and strain tensors are used to represent the material properties of materials. What you are probably interested in is the yield stress. At this point the material will begin to permanently deform. The ultimate stress would be the stress at which it breaks entirely. For materials like steel there is a fairly large difference between the yield stress and the ultimate stress, but for brittle materials like glass they are fairly close.
thank you for your response but can you give me a site to see an example?
another question: is yield stress the material not broken, ultimate stress the material is broken? like the body on rough plane and a force affect on it, if its not large enough to move the body the friction force not limiting, if its make it about to move the friction force is limiting? true?
 
Now that’s a question that would take a textbookCourse! In brief one can calculate the force on the glass plate knowing the Velocity of the ball and convert it to kinetic energy. The force, based on the stiffness, can be used to determine the contact stress and if high enough exceeding the strength of the glass it will cause a crack but it will not propagate through and break as it is very local.However at the back of the plate where the bending stress is in tension if that stress exceeds the ultimate then it will crack and break this time because it is not local anymore. The strength of the glass is dependent on the initial flaw size in the glass. It can vary anywhere between 1000 PSI and 40,000 PSI depending on the depth of the initial flaw. Glass, without the flaw, has a ridiculously high breaking strength.
 
PhanthomJay said:
Now that’s a question that would take a textbookCourse! In brief one can calculate the force on the glass plate knowing the Velocity of the ball and convert it to kinetic energy. The force, based on the stiffness, can be used to determine the contact stress and if high enough exceeding the strength of the glass it will cause a crack but it will not propagate through and break as it is very local.However at the back of the plate where the bending stress is in tension if that stress exceeds the ultimate then it will crack and break this time because it is not local anymore. The strength of the glass is dependent on the initial flaw size in the glass. It can vary anywhere between 1000 PSI and 40,000 PSI depending on the depth of the initial flaw. Glass, without the flaw, has a ridiculously high breaking strength.
Brilliant answer. Thank you
 
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