Mathematical series calculations

eljose
Messages
484
Reaction score
0
let be the series...

93712402...

Does anyone know what the general term is or how could it be calculated?..thanks.

-In fact if you are "Family's matter" fan you will know that this series appears in a chapter when Urkel is "jailed"...

the picture: http://www.paragonofvirtue.com/steve_urkel.jpg
 
Mathematics news on Phys.org
I really thought you knew more math than ask such a question, eljose.

There exist innumerably many sequences that have those digits as their first members.
 
eljose said:
let be the series...

93712402...

Does anyone know what the general term is or how could it be calculated?..thanks.

-In fact if you are "Family's matter" fan you will know that this series appears in a chapter when Urkel is "jailed"...

the picture: http://www.paragonofvirtue.com/steve_urkel.jpg

In what sense is that a "series"? Do you mean the sequence of digits
9, 3, 7, 1, 2, 4, 0, 2, ...

Do you have any reason to think there is a "general term" rather than just eight randomly chosen digits?
 
The general term is 1 apart from those terms you wrote down, obviously.
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...
Fermat's Last Theorem has long been one of the most famous mathematical problems, and is now one of the most famous theorems. It simply states that the equation $$ a^n+b^n=c^n $$ has no solutions with positive integers if ##n>2.## It was named after Pierre de Fermat (1607-1665). The problem itself stems from the book Arithmetica by Diophantus of Alexandria. It gained popularity because Fermat noted in his copy "Cubum autem in duos cubos, aut quadratoquadratum in duos quadratoquadratos, et...
I'm interested to know whether the equation $$1 = 2 - \frac{1}{2 - \frac{1}{2 - \cdots}}$$ is true or not. It can be shown easily that if the continued fraction converges, it cannot converge to anything else than 1. It seems that if the continued fraction converges, the convergence is very slow. The apparent slowness of the convergence makes it difficult to estimate the presence of true convergence numerically. At the moment I don't know whether this converges or not.
Back
Top