Maths question on making the subject

  • Thread starter questions_uk
  • Start date
In summary, the conversation is about making B, D, and C the subject in the equation A = 1/2 B (C - D) ^2. The correct solution for making B the subject is 2 x B = (C - D) ^ 2 / A or B = ( (C - D ^ 2) / A) / 2. However, it is unclear which version of the equation is being used. No solutions were provided for making D or C the subject.
  • #1
questions_uk
74
0
Hi.

A = 1/2 B (C - D) ^2

And I wanted to make B the subject

I have done:

2 x B = (C - D) ^ 2 / A

B = ( (C - D ^ 2) / A) / 2

Is this correct or not? And if not could you please amend it to make B the subject?

These are not the actual variables in the question by the way.


Also, how would I make D the subject in:

A = 1/2 B (C - D) ^2

Any help is appreciated. Thanks.
 
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  • #2
And one last question,
How would I make

C the subject in:

A = B / ( C x D x E) x gradient?
 
  • #3
Hi questions_uk! :smile:

(try using the X2 tag just above the Reply box :wink:)
questions_uk said:
A = 1/2 B (C - D) ^2

Do you mean A = B(C - D)2/2,

or A = (C - D)2/2B ? :confused:
 
  • #4
Hi.

From A = 1/2 B (C-D)2

And making B the subject.
 
  • #5
When someone asks for clarification, do NOT just repeat the original post!

Please answer the question! Is that
A= 1/(2B(C-D)^2) or A= (1/2)B(C-D)^2 ?
 

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