What Determines the Rank and Dimension of a Matrix's Solution Space?

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The row rank of the given matrix is determined to be 2 after reducing it to echelon form. Consequently, the column rank is also 2, as established by the rank theorem, which states that row rank equals column rank. The dimension of the solution space for the equation Mx=0 is calculated to be 2, derived from the number of columns minus the rank. This conclusion aligns with the principles of linear algebra regarding matrix ranks and solution spaces. The answer provided is confirmed to be correct.
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(a)Determine the row rank of the matrix,

1 1 1 1
1 1 2 5
2 2 0 -6

(b) What is the column rank of this matrix?
(c) What is the dimension of the solution space Mx=0

So this is my answer:

I have reduced my matrix into echelon form and i get

1 1 1 1
0 0 -1 -4
0 0 0 0

Therefore my row rank is 2 (the number of linearly independent rows)

Since by rank theorem, (row rank = column rank = determinental rank) the column rank is also 2.

And the dimension of the solution space is 2 (number of columns - rank)

Is this answer correct?

Thank you
Dylan
 
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yes, i think so
 
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