yuiop said:
Being a relativity forum, relativistic equations rather than Newtonian equations may be more appropriate so:
Shark 774 said:
Thanks for your response, that clears it up. You're right, this is a relativity forum and hence people may need to use a little more common sense, rather than others needing to be clearer.
First and foremost; Physics is an exact science, and words do matter. This is like saying, "Is that a soda?" When you really intended to say "Is that a "Coke 'a' Cola!"
Second; one of the main tenents of "Special Relativity" is the knowledge of the photon and its speed of light motion relative to matter. And this was why I added both equations, one that was relativistic at low speeds, and one that involved classical relativity.
Third; I answered you question, in a way that was to reveal how much "non-sense" was in your question. Or said in a nice way, to reveal that your question was not posed as clear as it should have been!
We are not in the 1800's anymore, in the 21st Century there is so much physics we
yuiop said:
Inertial Mass --- Photon
Total Energy Before Decay = Total Energy After Decay
\frac{M c^2}{\sqrt{1-v^2/c^2}} = \frac{M_{final} c^2}{\sqrt{1-v_{final}^2/c^2}} + hf
Just for info:
M is the rest mass and the original kinetic energy is:
\frac{M c^2}{\sqrt{1-v^2/c^2}} - M c^2
Maybe yuiop, Shark are not use to being specific; but the above equation is a bit more special relativity specific, using the following equations.
Rest Mass
m_{Net_0}
Relativistic Mass Before Decay
\frac{m_{Net_0}}{\sqrt{1-v^2_{Initial}/c^2_{Light}}}
Mass due to relativistic motion that is added to the Rest Mass Before Decay
\Delta m_{Motion} = \frac{m_{Net_0}}{\sqrt{1-v^2_{Initial}/c^2_{Light}}} - m_{Net_0}
Relativistic Doppler Frequency Observed
f_{Observed} = f_{Souce} \sqrt{\frac{1 - \frac{v_{final}}{c_{Light}}}{1 + \frac{v_{final}}{c_{Light}}}}
Inertial Mass --- Photon
Total Energy Before Decay = Total Energy After Decay
\frac{m_{Net_0}c^2_{Light}}{\sqrt{1-v^2_{Initial}/c^2_{Light}}} = \frac{m_{Net_0}c^2_{Light}}{\sqrt{1-v^2_{Final}/c^2_{Light}}} + h_{Planck}f_{Observed}
m_{Net_0}c^2_{Light} + \Delta m_{Motion}c^2_{Light} = \frac{m_{Net_0}c^2_{Light}}{\sqrt{1-v^2_{Final}/c^2_{Light}}} + (h_{Planck}f_{Souce}) \sqrt{\frac{1 - \frac{v_{final}}{c_{Light}}}{1 + \frac{v_{final}}{c_{Light}}}}
Hopefully this is relativistic enough for you!