Max Mass of Block C to Slide Block A & B Together

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SUMMARY

The discussion focuses on determining the maximum mass m_C that can be suspended from block A without causing blocks A and B to slide apart. The relationship between the forces acting on the blocks is established using the coefficients of kinetic friction (mu_k) and static friction (mu_s). The correct formula for m_C is derived from the equilibrium of forces, leading to the conclusion that m_C must satisfy the equation m_C = (m_A + m_B)(mu_k + mu_s). The participants clarify that the maximum acceleration is derived from the static friction force, which is m_B * g * mu_s, and emphasize the need to correctly equate forces rather than accelerations.

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Block B, of mass m_B, rests on block A, of mass m_A, which in turn is on a horizontal table top View Figure . The coefficient of kinetic friction between block A and the table top is mu_k and the coefficient of static friction between block A and block B is mu_s. A light string attached to block A passes over a frictionless, massless pulley and block C is suspended from the other end of the string.

http://session.masteringphysics.com/problemAsset/1007012/5/yf_Figure_5_66.jpg

What is the largest mass m_C that block C can have so that blocks A and B still slide together when the system is released from rest?

Okay, I get:

a = [m_c *g - (m_a + m_b)*g * mu_k]/(m_a + m_b)

and the max a is m_b * g * mu_s.

I set them equal, and end up with
m_c = (m_a + m_b)(mu_k + mu_s * m_b)

but that isn't correct. help?
 
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the max a is m_b * g * mu_s.
m_b * g * mu_s is a force, not an acceleration.
 
I'm stuck on the same problem. I get the same acceleration that you get, but for the Max Acceleration I get (mu_s * m_b * g) / m_b, and then i set them equal to each other, but I still get it wrong. There must be something I am overlooking.
 

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