Max radius of falling liquid drop

AI Thread Summary
The maximum radius of a falling liquid drop is calculated using the equation R=√(σ/gρ), where σ is surface tension, g is gravity, and ρ is the density of the liquid. For water at 20 degrees Celsius, the density is approximately 1000 kg/m^3 and the surface tension is 0.7275 J/m^2. While temperature can affect density, the problem does not specify temperature-dependent values, suggesting that it may not be crucial for this calculation. The key focus should be on correctly plugging in the given values and converting units to centimeters. Ultimately, the temperature might be included to test understanding rather than to influence the calculation significantly.
bengaltiger14
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The max radius a fallling liquid drop can have without breaking apart is given by the equation:

R=√(σ/gρ) where the rho is density of liquid (1000kg/m^3), and the surface tension is
.7275J/m^2. g is gravity

I am asked to determine the max radius of a drop in units of cm at 20 degrees celcius. Is this problem just a plug the values in problem and ignore the temperature? Is the temperature there just to throw me off?
 
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bengaltiger14 said:
The max radius a fallling liquid drop can have without breaking apart is given by the equation:

R=√(σ/gρ) where the rho is density of liquid (1000kg/m^3), and the surface tension is
.7275J/m^2. g is gravity

I am asked to determine the max radius of a drop in units of cm at 20 degrees celcius. Is this problem just a plug the values in problem and ignore the temperature? Is the temperature there just to throw me off?

The density σ does have a temperature dependence, but if the σ is a given with no reference to temperature in the problem, I'd have to wonder if the real problem is having you convert units correctly.

(Btw σ of water at 20 degrees is 0.9982071.)
 
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