Max Speed for 10 m Radius Spinning Drum Ride

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Homework Help Overview

The discussion revolves around determining the maximum speed of a spinning drum ride with a radius of 10 meters, while ensuring that the acceleration experienced by riders does not exceed 2g. Participants are exploring the relationship between speed, radius, and acceleration in the context of centripetal motion.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the use of trigonometric relationships and centripetal acceleration formulas. There are questions about the role of the angle θ and the implications of vertical walls on the calculations. Some participants suggest considering friction and the physical setup of the ride.

Discussion Status

The discussion is active, with various approaches being explored. Some participants have provided formulas and attempted calculations, while others are questioning the assumptions made about the ride's design and the nature of the problem. There is no explicit consensus yet, but productive dialogue is ongoing.

Contextual Notes

Participants are navigating constraints related to the physical setup of the ride, including the assumption of vertical walls and the potential impact of friction. The problem also involves interpreting the requirements of the question, particularly regarding the maximum speed versus angular speed.

Alcape
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Homework Statement


If a spinning drum ride cannot exceed a 10 m radius, and the riders are not to
experience an acceleration greater than 2g, what is the maximum speed at
which the drum can spin?


Homework Equations


No Idea


The Attempt at a Solution


I tried using (theta) = tan-1 of (rg/v2)
v2 = (tan(theta))/(rg)
v = (root) of (tan(theta))/(rg)
 
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Hi Alcape! :smile:

(have a theta: θ :wink:)
Alcape said:
If a spinning drum ride cannot exceed a 10 m radius, and the riders are not to
experience an acceleration greater than 2g, what is the maximum speed at
which the drum can spin?

I tried using (theta) = tan-1 of (rg/v2)
v2 = (tan(theta))/(rg)
v = (root) of (tan(theta))/(rg)

What's θ? :confused: You can assume that the drum's wall are vertical. :wink:

Now use the standard formula for centripetal acceleration :smile:
 
If the walls are vertical then it doesn't work as it's at 90 degrees and tangent of 90 degrees then it comes out to be a mathematical error
 
ah … you obviously haven't seen one of these at a fairground. :biggrin:

Yes, if the walls are smooth, it can't be done, but you can assume the walls are rough, so that friction will keep you up (or even that there's a ledge to stand on :wink:).
 
I now have the answer if you use the formula for acceleration:a=v2/r
and transpose it so that it becomes: v2 = a*r and therefore becomes:
v = √(a*r) and it comes out to be 4.47...
 
Hi Alcape! :smile:

(just got up :zzz: …)
Alcape said:
I now have the answer if you use the formula for acceleration:a=v2/r
and transpose it so that it becomes: v2 = a*r and therefore becomes:
v = √(a*r) and it comes out to be 4.47...

what about g ? :redface:

(and are you sure the question isn't asking for the angular speed?)
 
Yes I'm sure as this is question a and b asks for the angle
 

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