Max Speed of a Porsche 944 Turbo - 113317.4 W

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The Porsche 944 Turbo has an engine power of 217 hp, with 70% of that power, or 151.9 hp, reaching the wheels after accounting for drivetrain losses. The total mass of the car and driver is 1530 kg, with two-thirds of the weight over the drive wheels. The calculated power output of 113317.4 W is used to determine the force acting on the vehicle. However, the derived velocity of 11.336 m/s is significantly lower than expected for a car of this caliber, indicating a miscalculation in the force or other parameters. The discussion highlights the complexities of calculating maximum speed without complete data, particularly the cross-section area.
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A Porsche 944 Turbo has a rated engine power of 217 hp. 30% of the power is lost in the drive train, and 70% reaches the wheels. The total mass of the car and driver is 1530 kg, and two-thirds of the weight is over the drive wheels.

okay... sooo...

I know that P = F(car)*velocity = m*g*v+1/4*A*v^3
where A is the cross-section area.
But this problem doesn't have a cross-section area given.

Since the maximum power output is 217 hp and 70% of the power reaches the drive wheels.
P= (217hp)(0.70) = 151.9 hp

151.9hp * 746W/hp = 113317.4 W
and i don't know where to go with this.
 
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tomboi03 said:
A Porsche 944 Turbo has a rated engine power of 217 hp. 30% of the power is lost in the drive train, and 70% reaches the wheels. The total mass of the car and driver is 1530 kg, and two-thirds of the weight is over the drive wheels.

151.9hp * 746W/hp = 113317.4 W
and i don't know where to go with this.

113317.4 W reaches the wheels.The total weight of the wheels = 2/3 * 1530 * 9.8
I reckon that should help you find the velocity.
 
okay uh... the thing is...

I know P=F*v right?
so, if P= 113317.4
and F= 9996

i get v= 11.336 m/s...
and that is not nearly enough for a porsche to reach it's max speed... it's like the min speed if anything.
 
nvm i got it! hahaha ;) thanks!
 

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