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Homework Help: Max speed perpendicular to the wave's direction

  1. Aug 25, 2010 #1
    1. The problem statement, all variables and given/known data
    This question is part of a longer problem. I know the answer, but I don't know how they got their. Please provide a detailed explanation. Thanks.

    Question: Find the maximum speed perpendicular to the wave's direction of travel (the transverse speed).

    y(x,t)=2sin(4x-2t)

    2. Relevant equations
    The book gives a hint: find amplitude of dy/dt. Therefore, dy/dt=2cos(4x-2t)



    3. The attempt at a solution
    Period= pi
    Lambda= pi/2
    Frequency= 1/pi
    v=1/2
     
  2. jcsd
  3. Aug 25, 2010 #2

    kuruman

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    Incorrect. You forgot to apply the chain rule of differentiation.
     
  4. Aug 25, 2010 #3
    here u have to take x=0 as u r considering the perpendicular velocity. So once u assume that differentiate it and then u will get the max. value
     
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