Max speed perpendicular to the wave's direction

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Homework Statement


This question is part of a longer problem. I know the answer, but I don't know how they got their. Please provide a detailed explanation. Thanks.

Question: Find the maximum speed perpendicular to the wave's direction of travel (the transverse speed).

y(x,t)=2sin(4x-2t)

Homework Equations


The book gives a hint: find amplitude of dy/dt. Therefore, dy/dt=2cos(4x-2t)



The Attempt at a Solution


Period= pi
Lambda= pi/2
Frequency= 1/pi
v=1/2
 

Answers and Replies

  • #2
kuruman
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y(x,t)=2sin(4x-2t)

Homework Equations


The book gives a hint: find amplitude of dy/dt. Therefore, dy/dt=2cos(4x-2t)

Incorrect. You forgot to apply the chain rule of differentiation.
 
  • #3
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here u have to take x=0 as u r considering the perpendicular velocity. So once u assume that differentiate it and then u will get the max. value
 

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