Maximal normal subgroups proof

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Homework Statement


Prove that M is a maximal normal subgroup of G if and only G/M is simple

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The Attempt at a Solution


This is what I have so far.
Let f:G----> G/M be a group homomorphism with M a maximal normal subgroup of G. Suppose there exist a proper normal subgroup H of G/M
But then this would imply that f^(-1)(H) is a proper normal subgroup of G containing M which is contrary to assumption.

I am guessing the reverse goes something like suppose g: G/M---> G is a group homomorphism and suppose G/M is simple.
But then I am kind of stuck

Can anyone help?
 
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