Maximizing Rate of Change for V at Point P(2, -1, 2) in Rectangular Coordinates

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SUMMARY

The discussion focuses on maximizing the rate of change of the scalar field V at the point P(2, -1, 2) in rectangular coordinates, where V(x, y, z) = x² + 4y² + 9z². The maximum rate of change is calculated to be 37.094. The direction that produces this maximum rate of change is determined using the gradient, represented as ∇V, which points in the direction of the greatest increase of the scalar field. The gradient is defined mathematically as ∇f = ∂f/∂x + ∂f/∂y + ∂f/∂z.

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teng125
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potential V at the point P(2, -1, 2) in a rectangular
coordinate system is V (x, y, z) =x^2+4y^2+9z^2.


Find the direction that produces the maximum rate of change of V at P.

the max rate of change 37.094.
how to find direction that produces the maximum rate of change ??
 
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Also, if f is in x,y,z coordinates, then [itex]\nabla f= \frac{\partial f}{\partial x}+ \frac{\partial f}{\partial y}+ \frac{\partial f}{\partial z}[/itex].
 

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