Maximizing voltage across a load resistor?

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To maximize the voltage drop across a load resistor G in a loop circuit with fixed input voltage V and resistor R, the voltage divider equation is essential. The voltage drop across G can be expressed as VG = V * G / (R + G), and maximizing this requires finding when the derivative equals zero, suggesting that increasing G leads to a higher voltage drop. However, to maximize current into the load resistor, the focus should be on minimizing the total resistance (R + G). The optimal scenario for current occurs when G approaches zero, as this minimizes the total resistance. Understanding these relationships is crucial for effective circuit design.
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Hey, so I have this loop circuit that has some input voltage V in series with a resistor with a resistance of R and another in series resistor that is my load resistance, let's call it G. V and R are not variables, only G is.

I know that because of Jacobi's law, to maximize the power dissipated by the load resistance, you have to have G = R.

But I'm wondering how i should maximize the voltage drop across the load resistor? I just can't figure out how to write an equation and go from there.

Also, how can i maximize the current going into the load resistor?

Please help,
Thanks
 
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Mugged said:
Hey, so I have this loop circuit that has some input voltage V in series with a resistor with a resistance of R and another in series resistor that is my load resistance, let's call it G. V and R are not variables, only G is.

I know that because of Jacobi's law, to maximize the power dissipated by the load resistance, you have to have G = R.

But I'm wondering how i should maximize the voltage drop across the load resistor? I just can't figure out how to write an equation and go from there.

Also, how can i maximize the current going into the load resistor?

Please help,
Thanks

What is the voltage divider equation? That is what you use to do what you are asking about.

Assuming that V and Rs are fixed, you maximize the output voltage with an ______ circuit, and maximize the output current (a different situation) with a _______ circuit.
 
You mean kirchhoffs voltage eqn?

Its V - IR - IG = 0

im starting to think that i can maximize the voltage drop on the load resistor G by maximizing the resistance of G though...still don't know if that's right.
 
The voltage drop across the load resistor is given by VG=VG/(R+G), to find the maximum value of this function find when the derivative equals zero, so when R/(R+G)2= 0, which is when G equals infinity...basically the bigger the resistance the bigger the voltage drop across it.. if I am understanding your question..now to maximize the current going into the load resistor, well I=V/(R+G)...what would give a maximum value for I if G is the only variable?
 
OH! so minimizing R+G for current..i see.

Thanks a lot guys.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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