Maximum potential given a charge

AI Thread Summary
The discussion revolves around calculating the maximum charge and potential of a charged hollow metal sphere with a radius of 2 cm, given the breakdown field of air at 1 MV/m. The maximum charge calculated is approximately 4.4 x 10^-8 C. To find the potential, the relevant equation is V = Q/(4πε₀r), leading to a potential of 20 kV. The difference in the equations for electric field (E) and potential (V) is clarified, noting that the electric field varies with the square of the radius while potential varies linearly with radius. Understanding these relationships is essential for solving problems involving electric fields and potentials.
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Homework Statement



So the question states that we have a hollow metal sphere of radius 2cm that is charged up. We take the breakdown field of air to be 1MV/m. We are asked to:

a) Calculate the maximum amount of charge which can be placed on the sphere.
b) Calculate the maximum potential on the surface of the sphere.

Homework Equations



E = \frac{Q}{4\Piε_{0}r^{2}}

The Attempt at a Solution



a) 1\cdot10^{6} = \frac{Q}{4\Piε_{0}0.02^{2}}
So we get Q as being 4.4\cdot10^{-8}C​

However, I'm stuck with what to do next to get the potential. I'm not entirely sure I understand the question? Is it the potential between that space on the surface and the center of the sphere?

I know the answer (or at least it is given as 20kV) but I'm not sure how to arrive at that answer.

Cheers
 
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I think I might have cracked it. I realized that I also need the equation for potential which is:

V = \frac{Q}{4\Piε_{0}r}

Could someone please explain why it is r^{2} for electric field but r for potential?
 
You just need to recall how the potential and the field are related to Coulomb's force.
 
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