Max Shear Stress Homework: Find Max Stress

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SUMMARY

The maximum shear stress for the given parameters \(\sigma_{xx} = 120 \, \text{MN/m}^2\), \(\sigma_{yy} = 50 \, \text{MN/m}^2\), and \(\tau_{xy} = 40 \, \text{MN/m}^2\) is calculated using the equations for \(\sigma_{min}\) and \(\sigma_{max}\). The values obtained are \(\sigma_{min} = 31.8 \, \text{MN/m}^2\) and \(\sigma_{max} = 138.2 \, \text{MN/m}^2\). The discrepancy arises from the correct interpretation of the minimum shear stress, which is taken as zero in this context, leading to the maximum shear stress being calculated as \(0.5(\sigma_{max} - 0) = 69.1 \, \text{MN/m}^2\).

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Homework Statement


Find the maximum shear stress for \sigma _{xx} = 120 MN/m^2, \sigma _{yy} = 50 MN/m^2, \tau _{xy} = 40 MN/m^2

Homework Equations


\sigma _{min} = 0.5(\sigma _{xx}+\sigma _{yy})-0.5((\sigma _{xx}-\sigma _{yy})^2+4\tau _{xy} ^2 )^{0.5} = 31.8
\sigma _{max} = 0.5(\sigma _{xx}+\sigma _{yy})+0.5((\sigma _{xx}-\sigma _{yy})^2+4\tau _{xy} ^2 )^{0.5} = 138.2

The Attempt at a Solution


0.5(\sigma _{max} - \sigma _{min}) = 53.1 4. Problem
However, the correct answer states 0.5(\sigma _{max} - 0) = 69.1. Why is 0 taken as the minimum shear stress?
 
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Hint: the real world has a z axis as well.
 

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