# Maximum Short Circuit Current (Fault-Current) before breakdown of cond

1. Mar 17, 2014

### tipu_sultan

Here find some attached circuit of three phase cabinet which operation voltage is 400V /415V and have operated current 800A, fault current for 1 sec is 46 KA and have incoming and outgoing links with one phase Lighting and socket.

I want to know is there some method that one can calculate the short circuit current per second that the bus-bar can bear.

Moreover I also want to calculate the short circuit current for 3 second.

Is there any relation between the current and time in this case (directly, or Inversely Proportion) ?

Please provide me the formula if exist to calculate short circuit current (fault-current) in any time.

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• ###### Short-Curcuit-Current-1sec.jpg
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2. Mar 17, 2014

### jim hardy

Product of I2 X t = constant

think about that.... can you explain why?

3. Mar 17, 2014

The short-circuit current presents different values significant for withstand calculation:
ip[peak value] =k*sqrt(2)*I”k [IEC 60909-1 definition]
k=1.7-1.9[max.2] depending on X/R of the short-circuit grid.
it is the highest possible instantaneous value of the short-circuit current.
I”k = Initial symmetrical short-circuit current [rms].
The electromagnetic effect a circuit [physical] element has to withstand is defined as maximum force acting on this element. For three-phase short-circuit [according IEC 60865-1]:
Fm3=miuo/(4 *pi())*sqrt(3)*ip^2/am pi()=3.14159... [in excel language] am=distance between elements[busbars].
As you can see this value does not depends on time and in any case the busbar has to withstand it.
So you cannot allow a more elevated value of the short-circuit current.
The short-circuit current in time will decrease from I”k up to Ik-steady state short-circuit and in this time the losses produced in busbars have to be limited so not to heat the circuit element more than permitted.This is the thermal effect which the busbar has to withstand.
If Ithr =rated short-time withstand current
Tkr=rated short-time
If the new current Ith is LESS than Ithr then:Ith<=Ithr*sqrt(Tkr/Tk) Tk=new short-time.Tk>Tkr
If Tk<Tkr the new current has to be NOT MORE than Ikr in any case.
So 46 kA for 1 sec [rated] could be 26.55 kA for 3 sec.

4. Mar 18, 2014