Hello everyone, may I ask a question? I've been struggle with it for a few days. There's a cuboid (rectangular prism) R, with dimensions of x, y, z respectively. A point P is outside of R. The shortest distance between P and R is d. What is the maximum possible volume of the new hexahedron formed by P and R? Is something like d*sqrt((x*y)^2 + (y*z)^2 + (x*z)^2) + x*y*z close?