Maximum work delivered by a turbine

Click For Summary
SUMMARY

The discussion centers on calculating the maximum work delivered by a turbine using the Peng-Robinson equation of state in an adiabatic process. The user attempted to find the outlet temperature through trial and error, aiming for a change in entropy (ΔS) of zero, but only achieved a final value of approximately 21 J/mole·K. Despite using MATLAB for calculations and applying the relationship between enthalpy change (ΔH) and work, the results were incorrect. The user seeks alternative methods for calculating work and understanding the discrepancy in ΔS.

PREREQUISITES
  • Understanding of the Peng-Robinson equation of state
  • Knowledge of thermodynamic concepts such as adiabatic processes and entropy
  • Familiarity with enthalpy and its relationship to work
  • Proficiency in MATLAB for computational analysis
NEXT STEPS
  • Explore advanced thermodynamic cycles and their efficiency calculations
  • Learn about alternative equations of state for different conditions
  • Investigate MATLAB functions for thermodynamic property calculations
  • Study the implications of non-ideal gas behavior on entropy and enthalpy
USEFUL FOR

Engineers, thermodynamics students, and researchers involved in turbine design and performance optimization will benefit from this discussion.

HCM
Messages
1
Reaction score
0
Hi everyone :
I have a question: how to calculate the maximum work delivered by a turbine. Steam input T and pressure are given plus the outlet pressure only. Using Peng-Robinson equation of state. Adiabatic process.

I tried to find outlet temperature by trial and error using Peng-Robinson EOS until delta S (S2-S1)=0, (S is entropy) . but delta S never approached 0 . its final value was around 21 j/mole.K . I used it though to calculate delta H (H2-H1) because delta H = work . (H is the enthalpy)... but the answer was wrong very wrong >> I used MATLAB for my calculations . I'm sure of the equations and everything . So is there another way to calculate the work?
and anyone knows why delta S didn't even approach 0 !

Thanks in advance :) ..
 
Physics news on Phys.org
Show us what you did to find the conditions at which ΔS=0.

Chet
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
2
Views
3K
  • · Replies 1 ·
Replies
1
Views
4K
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 15 ·
Replies
15
Views
5K
  • · Replies 7 ·
Replies
7
Views
6K
  • · Replies 4 ·
Replies
4
Views
9K
  • · Replies 3 ·
Replies
3
Views
5K