Maxiumum Incident power on solar cell ?

AI Thread Summary
The discussion centers on determining the total incident solar power (Pin) for a dual junction solar cell simulation. The standard reference value for solar power at ground level is approximately 1000 W/m2, which is commonly used for testing and certification of photovoltaic cells. However, actual solar power can vary significantly due to local weather conditions, time of day, and atmospheric factors. A light meter is recommended for accurate measurements, as personal experiences indicate that actual power can be much lower than the standard value. Understanding these variations is crucial for calculating the efficiency of solar cells accurately.
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Hi
I have simulated a dual junction(Multijunction) solar cell of thickness 10 microns and length 20 microns in silvaco atlas device simulator. In order to calculate its efficiency i need exact value of incident solar power i.e Pin for the above said structure.

These are the parameters obtained from IV graph:
Isc=9.25A
Voc=1.32V
Pmax=9.828W
FF=0.80
To find out efficiency i need Pin(Total Incident solar power) for the mentioned structure length and thickness.
 
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The power of sunlight at the ground level, when all the (mean) atmospheric dissipations and reflections have been detracted, is very close to 1000 W/m2 (outside the atmosphere it's value is 1367 W/m2 at the mean distance Sun-Earth).

1000 W/m2 is also the standard reference value used for testing and certification of PV cells.
 
Daiquiri said:
The power of sunlight at the ground level, when all the (mean) atmospheric dissipations and reflections have been detracted, is very close to 1000 W/m2 (outside the atmosphere it's value is 1367 W/m2 at the mean distance Sun-Earth).

1000 W/m2 is also the standard reference value used for testing and certification of PV cells.

Pin = 1000W/m2 = 100mW/cm2 = 645mW/in2
.
is generally accepted power input on a solar cell, which occurs under certain optimum conditions. In practical situation the value differs from day to day and even from hour to hour. The best way to find the exact input power at certain time is to use a 'light meter'.

I once calculated the efficiency using 100mW/cm2, then when I used a light meter to verify the number, I found power in the AM hours in my area (south-eastern USA) actually is 50mW/cm2.
 
Neandethal00 said:
I once calculated the efficiency using 100mW/cm2, then when I used a light meter to verify the number, I found power in the AM hours in my area (south-eastern USA) actually is 50mW/cm2.

1000 w/m2 is the standard value of irradiation, used for certification and comparison of PV cells - which is the case here, if I understood it well.

For example, see this tech sheet of a Sharp 167 W module: http://www.abcsolar.com/pdf/sharp167.pdf - the bottom of the page 2, where it reads "standard test conditions".

Then of course, the actual value of irradiation will strongly depend on the local (geographical) weather conditions, like clouds, air humidity, air pollution, period of the year, morning, noon or evening... etc.

A bit like when we say that the air density is 1.225 kg/m3. It is a standard reference value valid for dry air at 15 °C and 101325 Pa of air pressure, but as soon as one of these conditions change, the value of density will change too.

Cheers!
 
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