Maybe a dumb question on standard error in equations

AI Thread Summary
To evaluate the standard error in the velocity calculation using the formula v = sqrt(2*g*change in y), first calculate the velocity using the nominal value of change in y (12.10 cm). Then, determine the velocity using the upper (12.16 cm) and lower (12.04 cm) bounds by plugging these values into the formula. The average of these two velocities will provide a central value, while the difference between them can be used to estimate the standard error. An algebraic approximation can also be applied for small changes, using the formula sqrt(x + dx) to refine the error calculation. This method effectively incorporates the standard error into the final velocity result.
JazzyJones
Messages
20
Reaction score
0

Homework Statement



I am using a value of change in y say 12.10 cm + or - .06cm.

I am trying to find velocity using the formula
v= sqrt(2*g*change in y)

how do I evaluate this equation with my standard error? because I can't just add or subtract the .06cm after since I will have a value for velocity now.

Homework Equations





The Attempt at a Solution

 
Physics news on Phys.org
Can you just plug in 12.10 cm to get v and then plug in 12.10 cm + .06cm and 12.10 cm - .06cm to figure out the error in v?
 
i'm not sure if this was correct but, I plugged in the value with + then plugged in te value with -. Average the two values, and did + or - the difference between the two
 
JazzyJones said:
i'm not sure if this was correct but, I plugged in the value with + then plugged in te value with -. Average the two values, and did + or - the difference between the two
That'll work. The algebraic way is to approximate sqrt(x + dx) = sqrt(x)sqrt(1+dx/x) as sqrt(x)(1+dx/2x) for small dx.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top