Mean molar mass after combustion in a combustion engine

AI Thread Summary
To calculate the mean molar mass after combustion in a combustion engine, the balanced reaction equation for the combustion of butane (C4H10) is essential. The problem involves determining the coefficients α, β, and γ for water, carbon dioxide, and nitrogen, respectively, based on the given masses of air and fuel. The participant has attempted to balance the equation by calculating the number of molecules of oxygen and nitrogen but is struggling to arrive at the correct mean molar mass. Assistance is sought in balancing the equation and calculating the mean molar mass accurately. Providing detailed calculations is necessary for effective guidance.
ChristopherJ
Messages
4
Reaction score
0

Homework Statement


The problem is to calculate the mean molar mass of the reaktion below, which takes place in a combustion engine.

C4H10 + z(0.79N2 + 0.21O2) → αH2O + βCO2 + γN2

where the molar masses for the different molecules/atoms are:
MH2O = 18, MCO2 = 44, MN2 = 28, MO2 = 32, MC = 12, MH = 1.

The mass of the air in the cylinder before combustion is 2.39905 grams. The mass of the fuel in the cylinder is 45.0 milligrams.

Homework Equations


See above


The Attempt at a Solution


I have tried to balance the equation above by calculating the amount of molecules of oxygen and nitrogen in the cylinder and the amount of molecules in the fuel to get α, β and γ. And then use these values to balance the reaction equation above. The mean molar mass can be calculated by dividing the right hand side by the amount of molecules at hand.

But, I don't get the right answer by doing this. Can anyone help me with this?

I am very grateful for answers!

Best regards
Christopher
 
Physics news on Phys.org
Without showing your calculations, you won't get much help.
 
Thread 'Confusion regarding a chemical kinetics problem'

Thread 'Confusion regarding a chemical kinetics problem'

TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
View full post »

Thread 'Prove that evolution is constant (Provide at least two arguments to support your position)'

I don't get how to argue it. i can prove: evolution is the ability to adapt, whether it's progression or regression from some point of view, so if evolution is not constant then animal generations couldn`t stay alive for a big amount of time because when climate is changing this generations die. but they dont. so evolution is constant. but its not an argument, right? how to fing arguments when i only prove it.. analytically, i guess it called that (this is indirectly related to biology, im...
View full post »

Similar threads

Automotive Loss of gaseous volume because of fuel combustion
Replies
2
Views
1K
Work done by Octane Combustion Engine
Replies
2
Views
2K
Automotive Ozone Enhanced Combustion of Water/Diesel Emulsion in CI Engines
Replies
6
Views
2K
The combustion of petrol can be approximately represented by the
Replies
1
Views
2K
Calculate combustion engine torque
Replies
5
Views
10K
Heat transfer and combustion problem
Replies
7
Views
3K
How to calculate the efficiency of a fuel engine
Replies
2
Views
3K
Is Decane a Viable Alternative to Octane for Engine Combustion?
Replies
6
Views
6K
Thermodynamics.... Constant volume pressure of combustion
Replies
33
Views
7K
How Does Fuel Composition Affect Combustion Efficiency and Steam Generation?
Replies
9
Views
8K

Hot Threads

Recent Insights

Back
Top